1g of a metal , having no variable valency produces 1.67g of its oxide when heated in air. It's carbonate contains 28.57percent of the metal. How much oxide will be obtained by heating 1g of carbonate?

To solve this problem, we need to break it down step by step. We know that 1 gram of the metal produces 1.67 grams of its oxide when heated in air. Additionally, we have information about the carbonate of the metal, which contains 28.57% of the metal. Our goal is to find out how much oxide will be obtained by heating 1 gram of the carbonate.

Understanding the Composition of the Carbonate

First, let's determine how much of the carbonate is made up of the metal. Since the carbonate contains 28.57% of the metal, we can calculate the mass of the metal in 1 gram of the carbonate:

• Mass of metal in carbonate = 28.57% of 1g = 0.2857g

Determining the Amount of Oxide Produced

Next, we need to find out how much oxide is produced from this amount of metal. From the information given, we know that 1 gram of the metal produces 1.67 grams of oxide. Therefore, we can set up a proportion to find out how much oxide is produced from 0.2857 grams of the metal:

• Oxide produced from 1g of metal = 1.67g
• Oxide produced from 0.2857g of metal = (1.67g * 0.2857g) / 1g

Calculating this gives us:

• Oxide produced = 1.67g * 0.2857 = 0.476g (approximately)

Final Calculation

Thus, when we heat 1 gram of the carbonate, we can expect to obtain approximately 0.476 grams of the oxide. This result is derived from the direct relationship between the mass of the metal and the mass of the oxide produced during the heating process.

In summary, by understanding the composition of the carbonate and applying the conversion factor from metal to oxide, we can effectively determine the amount of oxide produced from the carbonate. This method can be applied to similar problems involving metal oxides and carbonates.