For the reactionCaCO3 (s) <=> CaO (s) + CO2 (g), Kp = 0.5 atm at 250C . If 20 gm of CaCO3 is placed ina closed container at 250C, calculate the amount of CO2 produced at equilibrium.(a) 20 gm (b) 44gm (c) Data insufficient (d) None of these--------------------------------------------------------------------------------------------------------------------Sir,I proceeded as shown below , am I right or wrong Please give detailed solutionKp = Kc (RT)n Here n = 1So,Kc = Kp/RT = 0.5/(0.0821* 298) = 0.0204 -------------------------------- (1)Now,CaCO3 (s) <=> CaO (s) + CO2 (g)20/100 0 0At equilibrium0.2 - x x xSo, Kc = x-------------(2) as CaO and CaCO3 are solidFrom (1) and (2)x = 0.0204 moles = 0.0204 * 44 gm = 0.9 gmPlease reply soon

Anurag Kishore , 14 Years ago

Grade 12