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0.3g of an oxalate was dissolved in the 100 ml solution.the solution required n/20 KMnO^4 FOR COMPLETE OXIDATION.THE PERCENTAGE OXLATE ION IS

jauneet singh , 16 Years ago
Grade 12
anser 1 Answers
Askiitians Tutor Team

To determine the percentage of oxalate ion in the solution, we first need to understand the reaction involved and how to relate the amount of oxalate to the volume of potassium permanganate (KMnO4) used for titration. Let's break this down step by step.

Understanding the Reaction

Oxalate ions (C2O4^2-) can be oxidized by potassium permanganate in an acidic medium. The balanced chemical equation for this reaction is:

  • 5 C2O4^2- + 2 MnO4^- + 16 H^+ → 10 CO2 + 2 Mn^2+ + 8 H2O

This equation tells us that 5 moles of oxalate react with 2 moles of permanganate. This stoichiometry will be crucial for our calculations.

Calculating Moles of KMnO4

Next, we need to find out how many moles of KMnO4 were used in the titration. Since you mentioned that the solution required N/20 KMnO4, we can calculate the moles based on the volume used.

First, let's convert N/20 to molarity. N/20 means that the normality is 0.05 N (since N/20 = 1/20). For KMnO4, which has a valency of 5 in this reaction, the molarity (M) is equal to the normality (N) divided by the number of electrons transferred per mole of KMnO4. Thus, the molarity is also 0.05 M.

If we assume that 'V' is the volume of KMnO4 used in mL, the moles of KMnO4 can be calculated as follows:

  • Moles of KMnO4 = Molarity × Volume (in L)
  • Moles of KMnO4 = 0.05 × (V/1000)

Relating KMnO4 to Oxalate

From the balanced equation, we know that 2 moles of KMnO4 react with 5 moles of oxalate. Therefore, we can set up a ratio to find the moles of oxalate:

  • 5 moles of C2O4^2- / 2 moles of KMnO4 = x moles of C2O4^2- / (0.05 × V/1000)

From this, we can solve for x (the moles of oxalate):

  • x = (5/2) × (0.05 × V/1000)

Calculating Mass of Oxalate

Now, we need to convert moles of oxalate to grams. The molar mass of oxalate (C2O4^2-) is approximately 88 g/mol. Therefore, the mass of oxalate can be calculated as:

  • Mass of oxalate = Moles of oxalate × Molar mass
  • Mass of oxalate = x × 88

Finding the Percentage of Oxalate

Finally, to find the percentage of oxalate in the original 0.3 g sample, we use the formula:

  • Percentage of oxalate = (Mass of oxalate / Total mass of sample) × 100

Substituting the values we have:

  • Percentage of oxalate = [(5/2) × (0.05 × V/1000) × 88 / 0.3] × 100

At this point, you would need the specific volume of KMnO4 used in the titration to calculate the exact percentage of oxalate in the solution. Once you have that volume, you can plug it into the equation and solve for the percentage of oxalate ion present in your original sample.

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