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Plz explain Threshold frequency and kinetic energy of photoelectrons Plz explain Threshold frequency and kinetic energy of photoelectrons
Plz explain Threshold frequency and kinetic energy of photoelectrons
Threshold frequency (v0) and kinetic energy of photoelectrons For each metal, there is a characteristic minimum frequency – the threshold frequency (v0) – below which the photoelectric effect does not occur. Red light (v = 4.3 – 4.6 × 1014 Hz), for example, of any intensity may shine on a piece of potassium for hours but no photoelectrons will be released. But as soon as even a very weak yellow light (v = 5.1 × 5.2 × 1014 Hz) shines on potassium, the photoelectric effect is observed. The threshold frequency, v0 for potassium is 5 × 1014 Hz. For photoelectric effect to occur, the striking photon should have frequency more than that of the threshold frequency. If a photon of frequency (v) strikes a metal atom whose will be emitted only if v > v0. Since the striking photon has energy equal to hv and the minimum energy required to eject electron is hv0 (also called work function, W0) then hv – hv0 is transformed as the kinetic energy of the photoelectron (½ mev2) where me is the mass of electron and v its velocity. Since total energy has to conserved, one may write Einstein’s equation as hv – hv0 = ½ mev2 = kinetic energy of electron
Threshold frequency (v0) and kinetic energy of photoelectrons
For each metal, there is a characteristic minimum frequency – the threshold frequency (v0) – below which the photoelectric effect does not occur. Red light (v = 4.3 – 4.6 × 1014 Hz), for example, of any intensity may shine on a piece of potassium for hours but no photoelectrons will be released. But as soon as even a very weak yellow light (v = 5.1 × 5.2 × 1014 Hz) shines on potassium, the photoelectric effect is observed. The threshold frequency, v0 for potassium is 5 × 1014 Hz. For photoelectric effect to occur, the striking photon should have frequency more than that of the threshold frequency. If a photon of frequency (v) strikes a metal atom whose will be emitted only if v > v0. Since the striking photon has energy equal to hv and the minimum energy required to eject electron is hv0 (also called work function, W0) then hv – hv0 is transformed as the kinetic energy of the photoelectron (½ mev2) where me is the mass of electron and v its velocity. Since total energy has to conserved, one may write Einstein’s equation as hv – hv0 = ½ mev2 = kinetic energy of electron
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