Determine the molecular formula of an oxide of sulphur containing 50% sulphur

Dear pallavi

percentage of sulpher =50%

percentage of oxygen = 100-50 =50%

 number of molecule of sulpher = 50/32=1.5625

 number of  molecules of oxygen = 50/16 =3.125

 so simple ration of molecules are = S/O = 1/2

so emperical formula = SO₂

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