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1 litre mixture of CO and CO2 is taken. This is passed through a tube containing red hot charcoal. The volume now becomes 1.6 litre. The volumes are measured under the same conditions. Find the composition of mixture by volume.
Suppose there is x litre CO and (1-x)L CO2. Here x litre (1-x)L CO2 reacts with C as C + CO2 --> 2CO. Then the final volume would be x + (1-x) + (1-x) =2 -x = 1.6; so x = 0.4L CO and 0.6L CO2
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