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Grade Upto college levelPhysical Chemistry

1 litre mixture of CO and CO2 is taken. This is passed through a tube containing red hot charcoal. The volume now becomes 1.6 litre. The volumes are measured under the same conditions. Find the composition of mixture by volume.

vamshi

12 Years agoGrade Upto college level

4 Answers

Nandakumar UK

12 Years ago

Suppose there is x litre CO and (1-x)L CO_2.Here x litre (1-x)L CO₂ reacts with C as C + CO₂ --> 2CO. Then the final volume would be x + (1-x) + (1-x) =2 -x = 1.6; so x = 0.4L CO and 0.6L CO₂

Regards :)

Priyanshu

8 Years ago

Let the volume of CO=a litresAnd volume of CO2=b litres So,a+b=1And when it is passed through Charcoal tube, only CO2 will react,CO2 +C=2COb litres. 2b litresNow,a+2b=1.6And a+b= 1So,b= 0.6 litres and a is 0.4 litresAlso b=60%a=40%

Krish Gupta

6 Years ago

Suppose there is x litre CO and (1-x)L CO_2.Here x litre (1-x)L CO₂ reacts with C as C + CO₂ --> 2CO. Then the final volume would be x + (1-x) + (1-x) =2 -x = 1.6; so x = 0.4L CO and 0.6L CO₂

Thanks

Kushagra Madhukar

5 Years ago

Dear student,

Please find the solution to your problem below.

Suppose there is x litre CO and (1-x)L CO_2.

Here x litre (1-x)L CO₂ reacts with C as C + CO₂ → 2CO.

Then the final volume would be x + (1-x) + (1-x) =2 – x = 1.6;

so x = 0.4L CO and 0.6L CO₂

Hope it helps.

Thanks and regards,

Kushagra

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