1 litre mixture of CO and CO2 is taken. This is passed through a tube containing red hot charcoal. The volume now becomes 1.6 litre. The volumes are measured under the same conditions. Find the composition of mixture by volume.

Suppose there is x litre CO and (1-x)L CO_2. Here x litre (1-x)L CO₂ reacts with C as C + CO₂ --> 2CO. Then the final volume would be x + (1-x) + (1-x) =2 -x = 1.6; so x = 0.4L CO and 0.6L CO₂

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Let the volume of CO=a litresAnd volume of CO2=b litres So,a+b=1And when it is passed through Charcoal tube, only CO2 will react,CO2 +C=2COb litres. 2b litresNow,a+2b=1.6And a+b= 1So,b= 0.6 litres and a is 0.4 litresAlso b=60%a=40%