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the number of neutrons present in 44 g 14CD4 is
Molar mass of CD4=14+2*4=22
No. of moles of CD4=44/22=2
No. of neutron in 1 mole CD4=(8+4)*Na
=12*Na(Na is avogadro''s number, i.e. 6.022*10^23)
No. of neutron in 2 mole =24*Na
no. of moles= 44/(14+8) = 2
1 14C has 8 neutrons
1 2D has 2 neutrons
1 CD4 molecule has 16 neutrons.
2 moles will have = 16 * 6.022 * 1023 neutrons. = 9.635 * 1024
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