Flag Physical Chemistry> oxidation at anode of sulphate ion...
question mark

so4 -2 ---------------- s2o8 -2 + 2e- (ox.) how it is possible as there is no change in o. s. of s from sulphate ion to thionate i.e. +6 to +6

amit singhal , 12 Years ago
Grade 12th Pass
anser 2 Answers
vikash kumar

in S2O8 2- , there is a peroxy bond and while counting or calculating oxidation no. of sulphur, we take oxidation state of those oxygen atoms to be (-1) and so two O atoms with (-2) charge are going to (-1) oxidation state. so change in o.s. is in oxygen atoms not in the sulphur atoms. you can see the strusture of S2O8 2- ion given below having peroxy linkage in betweeen.

 

1205_84118_3503.gif

Thanks & Regards
Vikash Kumar, 
askIITians Faculty
B.Tech, IIT Delhi

Last Activity: 12 Years ago
Vikash Kumar

in S2O8 2- , there is a peroxy bond and while counting or calculating oxidation no. of sulphur, we take oxidation state of those oxygen atoms to be (-1) and so two O atoms with (-2) charge are going to (-1) oxidation state. so change in o.s. is in oxygen atoms not in the sulphur atoms. you can see the strusture of S2O8 2- ion given below having peroxy linkage in betweeen.

 

1205_84118_3503.gif

 

Thanks & Regards
Vikash Kumar, 
askIITians Faculty
B.Tech, IIT Delhi

 

 

ApprovedApproved
Last Activity: 12 Years ago
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments