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The solubility of silver chloride in 0.2 M NaCl is (Given Ksp AgCl = 1.8 × 10 −10 ) (A) 9 × 10 −10 M (B) 3.6 × 10 −10 M (C) 1.8 × 10 −11 M (D) 7.2 × 10 −10 M



The solubility of silver chloride in 0.2 M NaCl is (Given Ksp AgCl = 1.8 × 10−10)  


        (A)    9 × 10−10 M


        (B)    3.6 × 10−10 M


        (C)    1.8 × 10−11 M


        (D)    7.2 × 10−10 M


Grade:11

2 Answers

Amit Saxena
35 Points
9 years ago

Since NaCl is a strong electrolyte therefore the entire conc. of Cl− ions comes from NaCl Ksp AgCl = [Ag+] [Cl−]. If solubility of Ag+ = s in NaCl then

 

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India VK
42 Points
9 years ago

(A)

 

NaCl dissociates fully to give [Cl-] = 0.2 and contribution of [Cl-] from AgCl is negligible compared to it.

So, Ksp = [Ag+][Cl-] = 1.8*10^(-10)

 

Find [Ag+] which will be the solubility.

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