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The heat released in neutralisation of HCL and NaOH is 13.7kcal/mol, the heat released on neutralisation of NaOH with CH3COOH is 3.7 kcal/mol. The delta H' of ionistion of CH3COOH is?

The heat released in neutralisation of HCL and NaOH is 13.7kcal/mol, the heat released on neutralisation of NaOH with CH3COOH is 3.7 kcal/mol.
The delta H' of ionistion of CH3COOH is?

Grade:12

1 Answers

AskiitianExpert Pramod-IIT-R
47 Points
11 years ago
In the neutralization process ions come to each other and form salt and water. HCL is strong acid means H+ + CL- and NaOH is strong base means Na+ + OH- So there is not any energy loss to break HCL or NaOH. total energy will come as neutralisation. In Case of NaOH + CH3COOH NaOH is strong base means Na+ + OH- But CH3COOH is a weak acid so have to give some energy to form CHCOO- + H+ So total released energy== total energy in case of (strong acid + strong base) - energy require to form ions. 3.7 = 13.7 - energy require to form ions energy require to form ions= 10.00 kcal. only CH3COOH is weak nature So this enegy is ionisation energy of CH3COOH

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