Flag Physical Chemistry> Thermodynamics...
question mark

The heat released in neutralisation of HCL and NaOH is 13.7kcal/mol, the heat released on neutralisation of NaOH with CH3COOH is 3.7 kcal/mol. The delta H' of ionistion of CH3COOH is?

Chandrakesh Shukla , 15 Years ago
Grade 12
anser 1 Answers
AskiitianExpert Pramod-IIT-R

Last Activity: 15 Years ago

In the neutralization process ions come to each other and form salt and water. HCL is strong acid means H+ + CL- and NaOH is strong base means Na+ + OH- So there is not any energy loss to break HCL or NaOH. total energy will come as neutralisation. In Case of NaOH + CH3COOH NaOH is strong base means Na+ + OH- But CH3COOH is a weak acid so have to give some energy to form CHCOO- + H+ So total released energy== total energy in case of (strong acid + strong base) - energy require to form ions. 3.7 = 13.7 - energy require to form ions energy require to form ions= 10.00 kcal. only CH3COOH is weak nature So this enegy is ionisation energy of CH3COOH

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...