a ball of mass 200g is moving with velocity 10m/s if error in measurement of velocity is 0.1% the uncertainity in position in metres is ?

Mass of Ball (m)= 0.2kg
Velocity of the Ball=10m/s
ΔV=0.1%=10*0.1/100=0.01m/s
Hence, uncertainity in momentum,Δp=mΔV= 0.2*0.01kg-ms^-1=0.002kg-ms^-1
Let change in position=Δx
So by uncertainty principle,Δp*Δx=h/4π
…............................Δx=h/(4π*Δp)
..........................................Δx=6.64*10^-34/(4*3.14*0.002)m

Mass = 200g = 0.200kg Speed = 20cm = 0.20m/sKinetic energy = 1/2mv^2 = 1/2 (0.200kg )(0.20m/s)^2 = 0.004 joule.