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The enthalpy of formation of water is -270kj/mol. The enthalpy of neutralisation of strong base and acid is -57kj/mol. What is enthalpy of formation of OH-??

The enthalpy of formation of water is -270kj/mol. The enthalpy of neutralisation of strong base and acid is -57kj/mol. What is enthalpy of formation of OH-??

Grade:12

1 Answers

Sunil Kumar FP
askIITians Faculty 183 Points
9 years ago
The enthalpy of formation of water is -270kj/mol
H2 +1/2 O2 ------------>H2O ,\forallH =-270
The enthalpy of neutralisation of strong base and acid is -57kj/mol
H2O------------>H+ + OH- ,\forallH=57
enthalpy of formation is given by
Adding 1 and 2,we get
deltaH= -270+57 Kj/mol
=-213Kj/mol

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