25ml of a solution containing HCl and H2SO4 REQUIRED FOR NEUTRALISATION 24.10 ML of N/2 caustic soda solution. 25 ml of the same solution on precipitation with BaCl2 yielded 0.5218 gm of BaSO4 . what weight of each acid is contained in one its of the solution ?

HCl.......+..........H2SO4..........+NaOH.....>neutrallised completely.........equation(i)
..xmol..................ymol........24.1, N/2=0.5M


H2SO4+ BaCl2.........................>BaSO4..............equation(ii)
...................................................0.5218/233.43 mol=2.2 milli mole
As 1molof H2SO4 will give 1 mol of BaSO4
So, mol of H2So4=2.2millimole

Now from equation (i), mole of NaOH used=mole of OH=0.5*24.1=12.05milli mole=miili mole of H+ from both the acids
H+ given by H2SO4=2*2.2=4.4 milli mole
so H+ from HCl=12.05-4.4= 7.65milli mole = milli mole of HCl