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7.65 x 10 -3 moles NaNO3 require 3.06 x 10 -2 moles of a reducing agent to get reduced to NH3 . What is the n – factor of the reducing agent ?

7.65 x 10 -3 moles NaNO3 require 3.06 x 10 -2 moles of a reducing agent to get reduced to NH3 . What is the n – factor of the reducing agent ?

Grade:11

1 Answers

Kaushik
28 Points
10 years ago

oxidation state of nitrogen in NaNO3 is +5 which gets reduced to -3 in NH3.

hence,n-factor of NaNO3 in the reaction is 8.

In any reaction,no. of equivalents of the reactants consumed is the same.

Let assume n-factor of reducing agent to be n.

We get:

7.65 x 10 -3 x 8=3.06x10 -2 x n

thus, n=2

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