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Grade 11Physical Chemistry

Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of

0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol–1.

Profile image of Simran Bhatia
12 Years agoGrade 11
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4 Answers

Profile image of Radhika Batra
12 Years ago

0.375 M aqueous solution of sodium acetate

≡ 1000 mL of solution containing 0.375 moles of sodium acetate

∴Number of moles of sodium acetate in 500 mL

 

Molar mass of sodium acetate = 82.0245 g mole–1 (Given)

∴ Required mass of sodium acetate = (82.0245 g mol–1) (0.1875 mole)

= 15.38 g

 

Profile image of Lovish singla
8 Years ago
Molarity°mass/volume; put molarity to be0.375 and volume to be 500 ml we will get moles to be .188 and then multiply by 82 mass of sodium acetate
Profile image of aditya pradeep
7 Years ago
0.375M aqueous solution means that 0.375 mo of sodium acetate are present in 1000mL of solution.500mL of the solution should contain sodium acetate.
                                                                         =0.375/2 mole
 molar mass of sodium acetate   =82.0245 gmole-1 
mass of sodium acetate required=(0.375/2) (82.0245)
                                                    =15.38 g 
 
Profile image of ankit singh
5 Years ago

0.375 M solution of CH3COONa = 0.375 moles of CH3COONa/1000ml

No. of moles of CH3COONa in 500ml =10000.375×500=0.1875 moles
Molar mass of sodium acetate = 82.0245 g/mole
mass of CH3COONa required =82.0245×0.1875=15.38g