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Haemoglobin contains 0.33% of Iron by weight. The molecular weight of it is approx. 67200. The no. of iron atoms present in one molecule of Haemoglobin are ________?
Options :
(1) 1 (2) 2 (3) 4 (4) 6
Ist method:
a BE THE NO. OF ATOMS PRESENT IN ONE MOLECULE:
(a/67200) x 100 = 0.33 %
a = 3.9 = 4 (approx)
2nd method (direct method)
1) 100 - 0.33 grams of haemoglobin is present then,
moles of haemoglobin = 99.67/67200 = 0.00148
2) Moles of iron present in haemo. = 0.33/56 = 0.00589
Now, a/67200 moles of Haemoglobin contains 0.00589 moles then no. of moles of iron present in one molecule of haemo. = 0.00589 x Na/0.00148 x Na = 3.9 = 4
Approve plz!
(3)4
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