Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
Haemoglobin contains 0.33% of Iron by weight. The molecular weight of it is approx. 67200. The no. of iron atoms present in one molecule of Haemoglobin are ________?
Options :
(1) 1 (2) 2 (3) 4 (4) 6
Ist method:
a BE THE NO. OF ATOMS PRESENT IN ONE MOLECULE:
(a/67200) x 100 = 0.33 %
a = 3.9 = 4 (approx)
2nd method (direct method)
1) 100 - 0.33 grams of haemoglobin is present then,
moles of haemoglobin = 99.67/67200 = 0.00148
2) Moles of iron present in haemo. = 0.33/56 = 0.00589
Now, a/67200 moles of Haemoglobin contains 0.00589 moles then no. of moles of iron present in one molecule of haemo. = 0.00589 x Na/0.00148 x Na = 3.9 = 4
Approve plz!
(3)4
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !