Haemoglobin contains 0.33% of Iron by weight. The molecular weight of it is approx. 67200. The no. of iron atoms present in one molecule of Haemoglobin are ________?

Options :

(1) 1 (2) 2 (3) 4 (4) 6

Ist method:

a BE THE NO. OF ATOMS PRESENT IN ONE MOLECULE:

(a/67200) x 100 = 0.33 %

a = 3.9 = 4 (approx)

2nd method (direct method)

1) 100 - 0.33 grams of haemoglobin is present then,

moles of haemoglobin = 99.67/67200 = 0.00148

2) Moles of iron present in haemo. = 0.33/56 = 0.00589

Now, a/67200 moles of Haemoglobin contains  0.00589  moles
 then  no. of moles of iron present in one molecule of haemo. =  0.00589 x Na/0.00148 x Na = 3.9 = 4

Approve plz!

(3)4