Sunil Kumar FP
Last Activity: 10 Years ago
(density of mercury vapour/density of air) =6.92
In a given volume
mass of mercury vapour/mass of air) =6.92
mass of mercury vapour =6.92*29 g/mole
=200.68 g/mole
therefore number of mercury molecule =Na*200.68 atoms
Na is the avagadro number
=6.023*10^23*200.68 atoms
=1.208*10^26 atoms