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A solution of Na2SO4 in water is electrolysed using inert electrodes. The product at cathode and anode are respectively
(a) H2, O2
(b) O2, H2
(c) O2, Na
(d) O2, SO2
choose and explain
H + + 2 e - ---> 2H2 Cathode because it is a reduction reaction.
2H2O --> O2 + 4e - + 4H + Anode because it is an oxidation reaction.
so ans is A
Na2+ + 2e'' -> Na (Anode) 2SO4 2- -> 2SO3 + O2 + 4e'' (Cathode) The answer is C.
plz approve!
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