Flag Physical Chemistry> chemical-anergetics...
question mark

Given that H°ionisation of HX and HY as 45 and 20 kJ mol 1 respectively, then which of the following relation is correct?(a) pKa (HX) = pKa (HY) (b) pKa (HX) > pKa (HY)(c) pKa (HX) < pKa (HY) (d) pKa (HX) = pKa (HY) +log(45/20)please tell how also?

pratiksha agarwal , 11 Years ago
Grade 12
anser 1 Answers
Roshan Mohanty

Last Activity: 11 Years ago

Answer will be B
As the enthalpy is more in case of HX so more energy will be needed to ionize i.e it cannot be ionized easily
therefore , Ka will be less
which means pKa will be more for HX

Please approve 

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...