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a mixture is obtained by mixing the equal volumes of two solutions of pH=3 and pH=11.what will be the pH of the mixture?
Hi aastha,
let concentration of H+ be h
h1=10^-3
h2=10^-11
after mixing
h=(10^-3+10^-11)/2 ≈ 1/2 * 10^-3
pH = 3-0.3010 =2.699
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