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a 10L helium balloon at a pressure of 2 bar at 27C. some O2 is now in balloon and final volume is made 30L. the pressure also fell to 1 bar at same temperature. the partial pressure of O2 at end is?
Dear Himanshu,for helium.n(He)=P(1)V(1)/RT.for oxygen n(O)=P(2)V(2)/RTpartial pressure of O2= (mole fraction of O2).(Total pressure)= [ P(2).V(2) / P(2).V(2) + P(1).V(1) ].(1)= 1.30 / 1.30 + 2.10=30/30+20=3/5 barHence 0.6 bar (ANS)Regards.
p1v1=p2v2
let partial pressure of helium in 30L be P
then p1*30=2*10
p1=20/30 bar=2/3bar
partial pressure of O2=p2
p1+p2=1bar
partial pressure of O2=1/3 bar
Dear Himanshu,I am really sorry!ACTUALLY I MADE A MISTAKE IN THE ANS.SO HERES ANOTHER ATTEMPT:-For Helium,P(1)=2 bar,V(1)=10 L P(2)= x (let) , V (2)= 30 LHence, P(2)=x=2/3 bar. [ BY APPLYING BOYLES LAW. ]So Pressure of oxygen=1-2/3=1/3 bar = .33 bar (ANS).HOPE THIS HELPS.Regards.
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