A (g) + B(g) = C(g) + D(g)
Above equilibrium is established by taking A and B in a closed container. Initial concentration of A is twice the initial concentration of B. At equilibrium concentration of B and C are equal. Then find the equilibrium constant for the reaction, C(g) + D(g) = A(g) + B(g)

Question

mohit yadav · Answer

the equilbrium constant for the reaction is 2 if the conc. of D is same as that of conc.of B.

Vikas TU · Answer

A (g) + B(g) = C(g) + D(g) t=0 2a a 0 0 t=t 2a - x a - x x x At equilibrium concentration of B and C are equal. a - x = x a = 2x x = a/2 Now, at t=t 3a/2 a/2 a/2 a/2 K = [A] [B] /[C] [D] K = [3a/2] [a/2]/ [a/2] 2 K = 3a^2/4/a^2/4 K = 3 is te ansr. Approve! plz

Fggg · Answer

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A (g) + B(g) = C(g) + D(g) Above equilibrium is established by taking A and B in a closed container. Initial concentration of A is twice the initial concentration of B. At equilibrium concentration of B and C are equal. Then find the equilibrium constant for the reaction, C(g) + D(g) = A(g) + B(g)

A (g) + B(g) = C(g) + D(g)
Above equilibrium is established by taking A and B in a closed container. Initial concentration of A is twice the initial concentration of B. At equilibrium concentration of B and C are equal. Then find the equilibrium constant for the reaction, C(g) + D(g) = A(g) + B(g)

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A (g) + B(g) = C(g) + D(g) Above equilibrium is established by taking A and B in a closed container. Initial concentration of A is twice the initial concentration of B. At equilibrium concentration of B and C are equal. Then find the equilibrium constant for the reaction, C(g) + D(g) = A(g) + B(g)

A (g) + B(g) = C(g) + D(g) Above equilibrium is established by taking A and B in a closed container. Initial concentration of A is twice the initial concentration of B. At equilibrium concentration of B and C are equal. Then find the equilibrium constant for the reaction, C(g) + D(g) = A(g) + B(g)

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A (g) + B(g) = C(g) + D(g)
Above equilibrium is established by taking A and B in a closed container. Initial concentration of A is twice the initial concentration of B. At equilibrium concentration of B and C are equal. Then find the equilibrium constant for the reaction, C(g) + D(g) = A(g) + B(g)