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GIVEN concentration of KCl = 0.02
resistance =350ohm
sodium acetate the resistance = 1158ohms
equivalent conductance =27.7*10^-4ohm-1cm-1.
k=ρl/a
k/ρ=(27.7*10*10^-4)/350
k of sodium acetate= l/a*1/R
equvalent conductance =(k*1000)/.02
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