How to calculate equivalent weight in a diproportionation redox reaction? Give an example.
Anurag Kshatri , 11 Years ago
Grade 12
Physical Chemistry> redox...
1 Answers
Aman Bansal
Last Activity: 11 Years ago
Dear Anurag,
Equivalent weight of Oxidising and Reducing Agents
Equivalent weight of a substance (oxidant or reductant) is equal to molecular weight divided by number of electrons lost or gained by one molecule of the substance in a redox reaction.
Eq. wt. of O. A. = 
=
Eq. wt. of R. A. = 
= 
Table : Equivalent weight of few oxidising/reducing agents
|
Agents |
O. N. |
Product |
O. N. |
Change in |
Total |
Eq. wt. |
|
|
+ 6 |
|
+ 3 |
3 |
3 × 2 = 6 |
Mol. wt./6 |
|
|
+ 3 |
|
+ 4 |
1 |
1 × 2 = 2 |
Mol. wt./2 |
|
|
+ 2 |
|
+ 2.5 |
0.5 |
0.5 × 2 = 1 |
Mol. wt./1 |
|
|
– 1 |
|
– 2 |
1 |
1 × 2 = 2 |
Mol. wt./2 |
|
|
– 1 |
|
0 |
1 |
1 × 2 = 2 |
Mol. wt./2 |
|
|
+ 7 |
|
+ 2 |
5 |
5 × 1 = 5 |
Mol. wt./5 |
|
|
+ 7 |
|
+ 4 |
3 |
3 × 1 = 3 |
Mol. wt./3 |
|
|
+ 7 |
|
+ 6 |
1 |
1 × 1 = 1 |
Mol. wt./1 |
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