Grade 12Physical Chemistry

How to calculate equivalent weight in a diproportionation redox reaction? Give an example.

Anurag Kshatri

13 Years agoGrade 12

1 Answer

Aman Bansal

13 Years ago

Dear Anurag,

Equivalent weight of Oxidising and Reducing Agents

Equivalent weight of a substance (oxidant or reductant) is equal to molecular weight divided by number of electrons lost or gained by one molecule of the substance in a redox reaction.

Eq. wt. of O. A. =

Eq. wt. of R. A. =

Table : Equivalent weight of few oxidising/reducing agents

Agents	O. N.	Product	O. N.	Change in O. N. per atom	Total Change in O. N. per mole	Eq. wt.
	+ 6		+ 3	3	3 × 2 = 6	Mol. wt./6
	+ 3		+ 4	1	1 × 2 = 2	Mol. wt./2
	+ 2		+ 2.5	0.5	0.5 × 2 = 1	Mol. wt./1
	– 1		– 2	1	1 × 2 = 2	Mol. wt./2
	– 1		0	1	1 × 2 = 2	Mol. wt./2
(Acidic medium)	+ 7		+ 2	5	5 × 1 = 5	Mol. wt./5
(Neutral medium)	+ 7		+ 4	3	3 × 1 = 3	Mol. wt./3
(Alkaline medium)	+ 7		+ 6	1	1 × 1 = 1	Mol. wt./1

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