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How do i calculate the no. of lone pairs in ICl2 (iodine di chloride)?? can anyone plz expalin it only by using hybridisation and not with VSEPRT

How do i calculate the no. of lone pairs in ICl2 (iodine di chloride)??
can anyone plz expalin it only by using hybridisation and not with VSEPRT

Grade:11

1 Answers

Sunil Kumar FP
askIITians Faculty 183 Points
7 years ago
here we have ,the number of electron in iodine as 7.two chlorine atoms are there,it will use the two electron of iodine to make a covalent bond.the nuber of electrons left is 5.therfore the number of lone pair is 2.
actuslly the ion is ICL2-.In this case the number of lone pair is 3

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