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Physical Chemistry

What is the lowering of vapor pressure due to a solute in 1 molal aqueous solution at STP

Profile image of Anubhav Sharma
13 Years agoGrade
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2 Answers

Profile image of RAJORSHI PAUL
13 Years ago

ΔP=P°·xs where P° is the VP of pure liquid at STP, xs is the mole fraction of the solute. Here xs= 1/(1000/18)=.018. If P° is given then ΔP=.018xP°

Profile image of Anubhav Sharma
13 Years ago

In this question P(not) is not given