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What is the lowering of vapor pressure due to a solute in 1 molal aqueous solution at STP

7 years ago

Answers : (2)

RAJORSHI PAUL
36 Points
							

ΔP=P°·xs where P° is the VP of pure liquid at STP, xs is the mole fraction of the solute. Here xs= 1/(1000/18)=.018. If P° is given then ΔP=.018xP°

7 years ago
Anubhav Sharma
5 Points
							

In this question P(not) is not given 

7 years ago
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