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What is the lowering of vapor pressure due to a solute in 1 molal aqueous solution at STP

Anubhav Sharma , 13 Years ago
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RAJORSHI PAUL

ΔP=P°·xs where P° is the VP of pure liquid at STP, xs is the mole fraction of the solute. Here xs= 1/(1000/18)=.018. If P° is given then ΔP=.018xP°

Last Activity: 13 Years ago
Anubhav Sharma

In this question P(not) is not given 

Last Activity: 13 Years ago
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