Volume of bf gas 22000 normal meter cube carbon dioxide content 19 percent what is its mass in kgs?

To find the mass of the gas mixture you mentioned, we need to follow a few steps involving the volume, the composition of the gas, and the properties of the gases involved. Let's break it down step by step.

Understanding the Components

You have a volume of 22,000 normal cubic meters (Nm³) of a gas mixture that contains 19% carbon dioxide (CO₂). The first thing we need to do is determine the volume of CO₂ in that mixture.

Calculating the Volume of CO₂

To find the volume of CO₂, we can use the percentage content:

• Volume of CO₂ = Total Volume × Percentage of CO₂

Substituting the values:

• Volume of CO₂ = 22,000 Nm³ × 0.19 = 4,180 Nm³

Finding the Mass of CO₂

Next, we need to convert the volume of CO₂ to mass. To do this, we use the ideal gas law and the molar mass of CO₂. The molar mass of CO₂ is approximately 44 grams per mole.

Using the Ideal Gas Law

At standard temperature and pressure (STP), 1 mole of an ideal gas occupies about 22.4 liters, or 0.0224 cubic meters. Therefore, we can find the number of moles of CO₂ in the volume we calculated:

• Number of moles of CO₂ = Volume of CO₂ / Volume per mole

Substituting the values:

• Number of moles of CO₂ = 4,180 Nm³ / 0.0224 Nm³/mole ≈ 186,607 moles

Calculating the Mass

Now, we can find the mass of CO₂ by multiplying the number of moles by the molar mass:

• Mass of CO₂ = Number of moles × Molar mass

Substituting the values:

• Mass of CO₂ = 186,607 moles × 44 g/mole = 8,202,668 grams

To convert grams to kilograms, we divide by 1,000:

• Mass of CO₂ in kg = 8,202,668 g / 1,000 = 8,202.67 kg

Final Result

Thus, the mass of the carbon dioxide in the gas mixture is approximately 8,202.67 kg. This calculation illustrates how we can derive mass from volume and composition using the properties of gases.