Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

If dipole moment is (qxd) charge x bond length then why HF has higher dipole moment(1.9) & HI 0.4 when the d value is shorter of HF?

If dipole moment is (qxd) charge x bond length then why HF has higher dipole moment(1.9) & HI 0.4 when the d value is shorter of HF?

Grade:12

1 Answers

Naveen Kumar
askIITians Faculty 60 Points
6 years ago
This is because of very high electronegative value of fluorine. So the q vaue is quite high in this case which overcomes the increase in bond length in Case of HF.
So we should think about both the parameters ‘q’ and ‘d’ and product will give you the final result. We should also note that the dipolemoment of HCl is higher than the dipolemoment of HF. In this case, increase in bond length overcomes the charge difference and consequentely diploemoment inceases.

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free