0

Guest

Courses New

If dipole moment is (qxd) charge x bond length then why HF has higher dipole moment(1.9) & HI 0.4 when the d value is shorter of HF?

If dipole moment is (qxd) charge x bond length then why HF has higher dipole moment(1.9) & HI 0.4 when the d value is shorter of HF?

Grade:12

1 Answers

Naveen Kumar
askIITians Faculty 60 Points
9 years ago
This is because of very high electronegative value of fluorine. So the q vaue is quite high in this case which overcomes the increase in bond length in Case of HF.
So we should think about both the parameters ‘q’ and ‘d’ and product will give you the final result. We should also note that the dipolemoment of HCl is higher than the dipolemoment of HF. In this case, increase in bond length overcomes the charge difference and consequentely diploemoment inceases.

Think You Can Provide A Better Answer ?

Other Related Questions on Physical Chemistry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More