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The asolute abundance ratio of N14/N15 in atmospheric nitrogen found to be 272. Calculate atomic weight of atomespheric Nitrogen?
Hi kiran,
N14/N15=272/1
let a sample contains 1 atom of N15 then it contains 272 N14 atoms...
Atomic weight= (272*14 + 1* 15)/273
At. Wt.=14.0037
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