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The asolute abundance ratio of N14/N15 in atmospheric nitrogen found to be 272. Calculate atomic weight of atomespheric Nitrogen?

J Ravi Kiran , 16 Years ago
Grade 11
anser 1 Answers
askiitian.expert- chandra sekhar

Hi kiran,

N14/N15=272/1

let a sample contains 1 atom of N15 then it contains 272 N14 atoms...

Atomic weight= (272*14 + 1* 15)/273

At. Wt.=14.0037

Last Activity: 16 Years ago
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