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Grade: 11

                        

Isotopes of oxygen with mass number less than 16 undergo beta plus emission. Assuming an equi molar mixture of O 14 and O 15 , find a) the ratio of nucleide at the end of 1 Hr and b) at what time will the ratio of O 14 nuclei to O 15 nuclei be equal to 0.25.? Given that t 1/2 for O 14 =71sec and t 1/2 for O 15 = 124 sec.

11 years ago

Answers : (1)

askiitian.expert- chandra sekhar
10 Points
							

Hi Kiran,

O14 ----> N14         λ1

O15-----> N15         λ2

λ1=0.693/71=0.00976

λ2=0.693/124=0.00589

[A]01=[A]02

λ1* t=ln{ [A]01/[A]t1}----1

λ2* t=ln{ [A]02/[A]t2}-----2

After 1 hr=60*60 sec

a)from 1 and 2 :  eλ1*t/eλ2*t=[A]t2/[A]t1=e(λ1-λ2)*t=e0.00387*60*60=e13.932

b)[A]t2/[A]t1=e(λ1-λ2)*t=e0.00387*t=1/0.25

   0.00387*t = ln 4=2.303*2*0.3010 =1.386

   t= 1.386/0.00387 =358.14 sec


11 years ago
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