askiitian.expert- chandra sekhar
Last Activity: 15 Years ago
Hi Kiran,
O14 ----> N14 λ1
O15-----> N15 λ2
λ1=0.693/71=0.00976
λ2=0.693/124=0.00589
[A]01=[A]02
λ1* t=ln{ [A]01/[A]t1}----1
λ2* t=ln{ [A]02/[A]t2}-----2
After 1 hr=60*60 sec
a)from 1 and 2 : eλ1*t/eλ2*t=[A]t2/[A]t1=e(λ1-λ2)*t=e0.00387*60*60=e13.932
b)[A]t2/[A]t1=e(λ1-λ2)*t=e0.00387*t=1/0.25
0.00387*t = ln 4=2.303*2*0.3010 =1.386
t= 1.386/0.00387 =358.14 sec