the total number of ions present in 1ml of 0.1M barium nitrate solution is ???????????

Hello

Molarity = moles/litre

0.1 = X . 1000/1  ( converted  into ml)

X = 10^-4 moles or 0.0001 moles

and we know that Ba(NO₃₎₂ dissociates into Ba²⁺ + 2NO₃^-

the total no of ions = 3 in one mole 

so in 10^-4 moles = 

3 . 10^-4 . 6.023.10²³

solve it and you will get the ans

hope i helped..!

barium is in +2 state n total charge on nitrate is -1 therefore for every molecule of barium nitrate there will be 1 ion of barium n 2 ions of nitrate therefore molarity of ions is 3 times molarity of soln i.e. 0.3M