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the total number of ions present in 1ml of 0.1M barium nitrate solution is ???????????
Hello Molarity = moles/litre 0.1 = X . 1000/1 ( converted into ml) X = 10-4 moles or 0.0001 moles and we know that Ba(NO3)2 dissociates into Ba2+ + 2NO3- the total no of ions = 3 in one mole so in 10-4 moles = 3 . 10-4 . 6.023.1023 solve it and you will get the ans hope i helped..!
Hello
Molarity = moles/litre
0.1 = X . 1000/1 ( converted into ml)
X = 10-4 moles or 0.0001 moles
and we know that Ba(NO3)2 dissociates into Ba2+ + 2NO3-
the total no of ions = 3 in one mole
so in 10-4 moles =
3 . 10-4 . 6.023.1023
solve it and you will get the ans
hope i helped..!
barium is in +2 state n total charge on nitrate is -1 therefore for every molecule of barium nitrate there will be 1 ion of barium n 2 ions of nitrate therefore molarity of ions is 3 times molarity of soln i.e. 0.3M
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