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the total number of ions present in 1ml of 0.1M barium nitrate solution is ??????????? the total number of ions present in 1ml of 0.1M barium nitrate solution is ???????????
the total number of ions present in 1ml of 0.1M barium nitrate solution is ???????????
Hello Molarity = moles/litre 0.1 = X . 1000/1 ( converted into ml) X = 10-4 moles or 0.0001 moles and we know that Ba(NO3)2 dissociates into Ba2+ + 2NO3- the total no of ions = 3 in one mole so in 10-4 moles = 3 . 10-4 . 6.023.1023 solve it and you will get the ans hope i helped..!
Hello
Molarity = moles/litre
0.1 = X . 1000/1 ( converted into ml)
X = 10-4 moles or 0.0001 moles
and we know that Ba(NO3)2 dissociates into Ba2+ + 2NO3-
the total no of ions = 3 in one mole
so in 10-4 moles =
3 . 10-4 . 6.023.1023
solve it and you will get the ans
hope i helped..!
barium is in +2 state n total charge on nitrate is -1 therefore for every molecule of barium nitrate there will be 1 ion of barium n 2 ions of nitrate therefore molarity of ions is 3 times molarity of soln i.e. 0.3M
Dear Student,Please find below the solution to your problem.Molarity = moles/litre0.1 = X . 1000/1 ( converted into ml)X = 10^-4 moles or 0.0001 molesand we know that Ba(NO3)2dissociates into Ba2+ + 2NO3-the total no of ions = 3 in one moleso in 10^-4 moles =3 . 10^-4. 6.023.10^23Thanks and Regards
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