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the total number of ions present in 1ml of 0.1M barium nitrate solution is ???????????

the total number of ions present in 1ml of 0.1M barium nitrate solution is ???????????


 

Grade:11

3 Answers

Aditya Verma
33 Points
9 years ago

Hello

Molarity = moles/litre

0.1 = X . 1000/1  ( converted  into ml)

X = 10-4 moles or 0.0001 moles

and we know that Ba(NO3)2 dissociates into Ba2+ + 2NO3-

the total no of ions = 3 in one mole 

so in 10-4 moles = 

3 . 10-4 . 6.023.1023

solve it and you will get the ansLaughing

hope i helped..!

gauhar singh
7 Points
9 years ago

barium is in +2 state n total charge on nitrate is -1 therefore for every molecule of barium nitrate there will be 1 ion of barium n 2 ions of nitrate therefore molarity of ions is 3 times molarity of soln i.e. 0.3M

Rishi Sharma
askIITians Faculty 646 Points
one year ago
Dear Student,
Please find below the solution to your problem.

Molarity = moles/litre
0.1 = X . 1000/1 ( converted into ml)
X = 10^-4 moles or 0.0001 moles
and we know that Ba(NO3)2dissociates into Ba2+ + 2NO3-
the total no of ions = 3 in one mole
so in 10^-4 moles =
3 . 10^-4. 6.023.10^23

Thanks and Regards

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