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Grade: 11

                        

the total number of ions present in 1ml of 0.1M barium nitrate solution is ???????????

8 years ago

Answers : (3)

Aditya Verma
33 Points
							

Hello

Molarity = moles/litre

0.1 = X . 1000/1  ( converted  into ml)

X = 10-4 moles or 0.0001 moles

and we know that Ba(NO3)2 dissociates into Ba2+ + 2NO3-

the total no of ions = 3 in one mole 

so in 10-4 moles = 

3 . 10-4 . 6.023.1023

solve it and you will get the ansLaughing

hope i helped..!

8 years ago
gauhar singh
7 Points
							

barium is in +2 state n total charge on nitrate is -1 therefore for every molecule of barium nitrate there will be 1 ion of barium n 2 ions of nitrate therefore molarity of ions is 3 times molarity of soln i.e. 0.3M

8 years ago
Rishi Sharma
askIITians Faculty
614 Points
							Dear Student,
Please find below the solution to your problem.

Molarity = moles/litre
0.1 = X . 1000/1 ( converted into ml)
X = 10^-4 moles or 0.0001 moles
and we know that Ba(NO3)2dissociates into Ba2+ + 2NO3-
the total no of ions = 3 in one mole
so in 10^-4 moles =
3 . 10^-4. 6.023.10^23

Thanks and Regards
3 months ago
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