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Grade:

                        

calculate the pH of 0.32 M Naoh

8 years ago

Answers : (1)

Gaurav
askIITians Faculty
164 Points
							pOH = -log[0.32] = - log[3.2\times 10^-1]
= – log 3.2 +1 = -0.505 +1 = 0.5
pH = 14- pOH = 14-0.5 = = 13.5
6 years ago
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