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the ion product for liquid water kw varies with temperature, as indicated by the change in pkw . the definition of neutrality is [H+] = [OH-]. what is the pH of water at neutrality at 50C?
the dissociation constant for the reaction is given byH2O -------H+ +OH-Ka=[H+][OH-]/[H2O]The neutrality of water is at a temperature of 24.87 degree celsiusAs the temperature is increases the Kw =10^-14 of neutral water is decreaesd and at 50 degree celsius it is 10^-13.262.now,At 50 deg C Kw = 8.0x10^-14 = [H+][OH-][H+] = 2.828x10^-7pH = 6.55
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