the ion product for liquid water kw varies with temperature, as indicated by the change in pkw . the definition of neutrality is [H+] = [OH-]. what is the pH of water at neutrality at 50C?

the dissociation constant for the reaction is given by
H2O -------H+ +OH-
Ka=[H+][OH-]/[H2O]
The neutrality of water is at a temperature of 24.87 degree celsius
As the temperature is increases the Kw =10^-14 of neutral water is decreaesd and at 50 degree celsius it is 10^-13.262.
now,At 50 deg C Kw = 8.0x10^-14 = [H+][OH-]
[H+] = 2.828x10^-7
pH = 6.55