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the standard reduction potentals,E,for the half cells reactions are as
Zn=Zn2++2e;E=+0.76V
Fe=Fe+2+2e;E=0.41V
The emf of the cell reaction
Fe+2+Zn=Fe+Zn is
a)-0.35v
b)+0.35v d)-1.17v
c)1.17v
Hi,
Fe+2+Zn=Fe+Zn+2
E cell = -0.41+0.76
=0.35 V
ans is (b)
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