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passing 25 ml of a gaseous mixture of N 2 and NO over heated copper, 20 ml of the gas remained. Calculate the percentage of each in the mixture.

 


passing 25 ml of a gaseous mixture of N2 and NO over heated copper, 20 ml of the gas remained. Calculate the percentage of each in the mixture.

Grade:11

2 Answers

askiitian.expert- chandra sekhar
10 Points
12 years ago

hi nikit,

25 ml of N2 + NO

20 ml remained is N2

NO is absorbed

therefore 20% NO and 80% N2 are present.

Nikit Saraf
18 Points
12 years ago

Thank you very much for the answer sir. But the book from which i have taken the question says the answer is 60% of N2 and 40% of NO. And i also think but i m not sure about it that your assumption about only N2 being unreacted when N2 and NO  is passed over copper is totally correct. I think there also be some quantity of copper or NO which is left unreacted and which can account for the volume of the remaning gases. Sir, so which of the answers do consider as correct? I m also totally confused about it. So please hep me out!

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