Why lanthanum conf is [Xe]6s-2 5d1 ,instead it should be [Xe]6s-2 4f-1 as 4f has lower energy than 5d,n+l rule?
Please explain why is this so?
IT COMPLETELY VIOLATES AUFBAU PRINCIPLE (as 4f being of low energy is not given e- but 5d of higher energy is given the e- )
ALSO if this was true than how could the next element i.e. cerium have conf [Xe]6s-2 5d-1 4f-1 , here why then 4f is given priority and not 5d.
PLEASE EXPLAIN THIS CONTRADICTION
ALSO EXPLAIN THIS CONTRADICTION IN THE CASE OF ACTINIUM AND THORIUM .
PLEASE RESPOND URGENTLY
Why lanthanum conf is [Xe]6s-2 5d1 ,instead it should be [Xe]6s-2 4f-1 as 4f has lower energy than 5d,n+l rule?
Please explain why is this so?
IT COMPLETELY VIOLATES AUFBAU PRINCIPLE (as 4f being of low energy is not given e- but 5d of higher energy is given the e- )
ALSO if this was true than how could the next element i.e. cerium have conf [Xe]6s-2 5d-1 4f-1 , here why then 4f is given priority and not 5d.
PLEASE EXPLAIN THIS CONTRADICTION
ALSO EXPLAIN THIS CONTRADICTION IN THE CASE OF ACTINIUM AND THORIUM .
PLEASE RESPOND URGENTLY
IT COMPLETELY VIOLATES AUFBAU PRINCIPLE (as 4f being of low energy is not given e- but 5d of higher energy is given the e- )
ALSO if this was true than how could the next element i.e. cerium have conf [Xe]6s-2 5d-1 4f-1 , here why then 4f is given priority and not 5d.
PLEASE EXPLAIN THIS CONTRADICTION
ALSO EXPLAIN THIS CONTRADICTION IN THE CASE OF ACTINIUM AND THORIUM .
PLEASE RESPOND URGENTLY










