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A particle m starts with zero velocity along a line y=4d.The position of particle m varies as x=A*sin*omega*t , At omega*t=pi/2 , its angular momentum with respect to origin is??

Ranjita yadav , 13 Years ago
Grade 11
anser 1 Answers
Emaad Mulla

Last Activity: 13 Years ago

zero..

 

angular momentum = mvr

 

x=Asin(wt)

v=Awcos(wt)

 

at pi/2 cos (wt)=0

 

so v=0

 

so mvr =0...

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