A particle m starts with zero velocity along a line y=4d.The position of particle m varies as x=A*sin*omega*t , At omega*t=pi/2 , its angular momentum with respect to origin is??
Ranjita yadav , 13 Years ago
Grade 11
1 Answers
Emaad Mulla
Last Activity: 13 Years ago
zero..
angular momentum = mvr
x=Asin(wt)
v=Awcos(wt)
at pi/2 cos (wt)=0
so v=0
so mvr =0...
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