askiitian.expert- chandra sekhar
Last Activity: 15 Years ago
Hi Aditya,
Hi,
A---->B k1
A---->C k2
d[B]/dt = k1*[A] d[B] = k1*[A] dt
d[C]/dt = k2*[A] d[C] = k2*[A] dt
therefore [B]/[C] = k1/k2 = 1/9
[A]0 = [A]+[B]+[C]
[A]=[A]0e-(k1+k2)t
[A]=[A]0e-0.468
[A]0 = [A]e0.468
[A]0 = [A]+[B]+[C]
[A]e0.468= [A]+[B]+[C]
[A]*1.656= [A]+[B]+[C]
[A]*0.656=[B]+[C]
0.656*[A]/[C] = [B]/[C] + 1 = 1/9 +1 = 11/9
[C]/[A]=0.656*9/11=0.537