Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
calculate[H+] in solution that is 0.1M HCOOH and 0.1M HOCN Ka(HCOOH)=1.8*10-4& Ka(HOCN)=3.3*10-4
calculate[H+] in solution that is 0.1M HCOOH and 0.1M HOCN
Ka(HCOOH)=1.8*10-4& Ka(HOCN)=3.3*10-4
Hi Tejas, [H+][HCOO-]/[HCOOH]=1.8*10-4 (x+y)*x/(1-x)=1.8*10-4------(1) [H+][OCN-]/[HOCN]=3.3*10-4 (x+y)*y/(1-y)=3.3*10-4-------(2) (1)/(2)=x/y=1.8/3.3 considering 1-x≈1 and 1-y≈1 y=3.3*x/1.8 substituting in (1) 5.1/1.8 *x2 = 1.8*10-4 x=7.97*10-3 y=14.612*10-3 x+y=22.582*10-3 [H+]= 0.0226
Hi Tejas,
[H+][HCOO-]/[HCOOH]=1.8*10-4
(x+y)*x/(1-x)=1.8*10-4------(1)
[H+][OCN-]/[HOCN]=3.3*10-4
(x+y)*y/(1-y)=3.3*10-4-------(2)
(1)/(2)=x/y=1.8/3.3 considering 1-x≈1 and 1-y≈1
y=3.3*x/1.8
substituting in (1)
5.1/1.8 *x2 = 1.8*10-4
x=7.97*10-3
y=14.612*10-3
x+y=22.582*10-3
[H+]= 0.0226
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -