Q6.5 The enthalpy of combustion of methane, graphite and dihydrogen

at 298 K are, ?890.3 kJ mol?1 ?393.5 kJ mol?1, and ?285.8 kJ mol?1

respectively. Enthalpy of formation of CH4(g) will be

(i) ?74.8 kJ mol?1 (ii) ?52.27 kJ mol?1

(iii) +74.8 kJ mol?1 (iv) +52.26 kJ mol?1.

Dear Student,

According to the question,

Thus, the desired equation is the one that represents the formation of CH_4 (g) i.e.,

Enthalpy of formation of CH_4(g) = –74.8 kJ mol^–1

Hence, alternative (i) is correct.

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