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Q6.5 The enthalpy of combustion of methane, graphite and dihydrogen at 298 K are, ?890.3 kJ mol?1 ?393.5 kJ mol?1, and ?285.8 kJ mol?1 respectively. Enthalpy of formation of CH4(g) will be (i) ?74.8 kJ mol?1 (ii) ?52.27 kJ mol?1 (iii) +74.8 kJ mol?1 (iv) +52.26 kJ mol?1.


Q6.5 The enthalpy of combustion of methane, graphite and dihydrogen


at 298 K are, ?890.3 kJ mol?1 ?393.5 kJ mol?1, and ?285.8 kJ mol?1


respectively. Enthalpy of formation of CH4(g) will be


(i) ?74.8 kJ mol?1 (ii) ?52.27 kJ mol?1


(iii) +74.8 kJ mol?1 (iv) +52.26 kJ mol?1.


Grade:11

1 Answers

Aman Bansal
592 Points
11 years ago

Dear Student,

According to the question,

Thus, the desired equation is the one that represents the formation of CH4 (g) i.e.,

Enthalpy of formation of CH4(g= –74.8 kJ mol–1

Hence, alternative (i) is correct.

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