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let molecular masses be m1 and m2,
PV=nRT,P=(RT/V)(n1 + n2)
2 bar=(RT/V)*n1=(RT/V)*(1/m1)
3 bar=(RT/V)((1/m1)+(2/m2))
Last Activity: 13 Years ago
The Pressure of A + Pressure of B = 3 Bar (Given :Pressure when both gases are present in the flask under same conditions is 3bar)
Using Daltons law of partial Pressures, Pressure of B = 3-2=1bar
According to an ideal gas equation, For gas A
P1V=n1RT ==> P1V=(m1/M1)RT
Similarly for the gas B
P2V=n2RT ==> P2V=(m2/M2)RT
Diving both the Equ. We get P1/P2=m1M2/m2M1 ==>P1m2/P2m1=M2/M1
M2/M1= P1m2/P2m1
So the ratio of their Molecular masses(M2/M1)=(2*2)/(1*1)=(4:1)---(Ans)
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