Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
explain the pressure correction in Wander Wall correction.
(p+an^2/v^2).
shouldn't it be (p-an^2/v^2)
No it is (P+an^2/V^2) because in case real gas molecules are attracted by other molecules inthe container, so the pressure appear on the wall's of container is less than expected pressure. So some additional pressure is required so as to make it a pressure equal to the pressure of an ideal gas.
P correct=P observed + p
P is directly proportional to d^2
d=n/V
therefore, d is directly proportional to n^2/V^2 i.e, p=an^2/V^2
a is coefficient of attraction.
Don't forget to approve my answer!!
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !