Join now for JEE/NEET and also prepare for Boards Join now for JEE/NEET and also prepare for Boards. Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
Calculate the degree of ionisation of normal ZnSO 4 solutionat 373 k if its vapour pressure is 750mm. Calculate the degree of ionisation of normal ZnSO4 solutionat 373 k if its vapour pressure is 750mm.
Calculate the degree of ionisation of normal ZnSO4 solutionat 373 k if its vapour pressure is 750mm.
Hi, Recall that the total pressure of a solution is the sum of the partial pressures of the solvent and solute psolution = psolvent + psolute = xsolvent P°solvent + xsolute P°solute If the solute is non-volatile (no vapour pressure: P°solute = 0) then the total vapour pressure of solution is psolution = psolvent = xsolvent P°solvent (where x= mol fractn) now v.p of water at 373 k = 760 mm 750= x*760 => x = 750/760 1-x = mole fractn of solute = mol of solute/total moles(nearly = moles of water) = mol of solute/moles of water ZnSO4 -> Zn(+2) +SO4(-2) 0.5-y y y (1N= 0.5M) total moles of solute = 0.5+y total moles of solvent(water)=55.55 (in 1 lt) => 1-x = 0.5 + y /55.55 =>1-750/760= 1/76= 0.5+y /55.55 => y = 0.23 y = dissociation = 23%
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -