Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
Assuming the complete dissociation of HCl and the lead salt ,calculate how much HCl is to be added to a 0.001 M lead salt solution to just prevent precipitation when saturated with H2S?The concentration of H2S in its saturated solution is 0.1 M. KaH2S=1.1×10-23;KspPbS=3.4×10-28.
Hi Ankur,
[Pb+2] [S2-] = Ksp = 3.4 * 10^-28
[PbS] = [Pb+2] = 0.001 (saturated)
[S2-]= 3.4 * 10^-25
Ka = 1.1 * 10^-23 = [H+]2[S-2]/[H2S]
[H+]2 = 1.1/3.4 * 10^2 * 0.1
[H+] = 1.8
since due to the very small Ka value of H2S the H+ furnished by it is negligible.
Therefore the 1.8 M HCl is to be added.
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !