Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
an alpha particle of momentum p is bombarded on the nucleus the distance of the closest aproch is r if momentum of alpha particle is made 6 times the distance of the closest approch becomes
assume that when the alpha particle has momentum 'p', it is far enough from the nucleus so that its potential energy can be considered to be zero. kinetic energy= p2/2m, at closest approach kinetic energy=0, and potential energy=p2/2m=k/r, where k is a constant which can easily be obtained from elementary electrostatics. r=2mk/p2, thus r is inversely proportional to p2,
Therefore, if momentum of alpha particle is made 6 times, distance of closest approach becomes r/36
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !