Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

If d is the density of a solution of a solute(molar mass = W) in a solvent and "m" is the molality , then prove that molarity(M) of this solution is M = (1000d m)/(1000 + mW)

 If d is the density of a solution of a solute(molar mass = W) in a solvent and "m" is the molality , then prove that molarity(M) of this solution is
M = (1000d m)/(1000 + mW)


 


 

Grade:

1 Answers

SAGAR SINGH - IIT DELHI
879 Points
9 years ago

let weight of the solvent be w gm and weight of the solution be Wgm
then weight of the solvent=(W-w)gm

density D=W/V (V=volume of the solution)

molality m=(w x1000)/(M'x(W-w))

this implies, (W-w)=(w x1000)/(M'xm)

=> W=w [(1000+M'm)/M'm]

now,
molarity M=(w x1000)/(M' x V)

=> V=(w x1000)/(MxM')

now
D=W/V
=> D=[{(1000+M'm)/M'm}/{1000/MM'}]

=> D=[(1000+M'm)xMM'] / [1000x M'm]

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free