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50 ml 0.1 M NaOH is added to 50 ml of 0.1 M CH3COOH solution, what will be the final pH? please give me a detailed solution for this given that pKa=pKb= 4.7447 pKw= 14
after adding 50ml 0.1M NaOH in 50ml of 0.1M CH3COOH solution,there willbe made 50ml 0.1 M CH3COONa & there remaining 50ml 0.1M CH3COOH. total velocity=(50+50+50)=150ml.Molarity of CH3COOH=(50x0.1)/150=.0333M.Molarity of CH3COONa=(50x0.1)/150=.0333M.then pH=pKa+log [salt]/[acid]=4.7447+log [.0333]/[.0333]=4.7447+log 1=4.7447+0=4.7447.So the ans is pH=4.7447.
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