12g of an alkaline earth metal gave 14.8g of its nitride.Atomic wt of that metal is

Question

Ramesh V · Answer

let the metal be M with atmic wt. be x

so 3M + N₂ ---->M₃N₂

3x 3x+28

so, 12/3x = 14.8/(3x+28)

which in solving for x gives 40

the metal is calcium and its nitride is Ca₃N₂

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mohd atif chaudhary · Answer

Mass of metal is 12g and Mass of metal nitride is 14.8gm so Mass of nitride ion is 2.8 gm. By using equivalence law: Mass of metal / Mass of Nitride ion =Equivalent Mass of metal/14 12/2.8=3x/14 x=20 as x is equivalent weight by multiplying it with 2 which is valency of metal ion. We get 40. Before x is 3 is used which is valency of Nitride and 14 is Mass of N .

mohd atif chaudhary · Answer

Mass of metal is 12g and Mass of metal nitride is 14.8gm so Mass of nitride ion is 2.8 gm.By using equivalence law: Mass of metal / Mass of Nitride ion =Equivalent Mass of metal/14 12/2.8=3x/14x=20 as x is equivalent weight by multiplying it with 2 which is valency of metal ion. We get 40. Before x is 3 is used which is valency of Nitride and 14 is Mass of N .

Kushagra Madhukar · Answer

Dear student, Please find the solution to your problem. Let the metal be M with atmic wt. be x so 3M + N 2 ---->M 3 N 2 3x 3x+28 so, 12/3x = 14.8/(3x+28) Hence, x = 40 Hence, the metal is calcium and its nitride is Ca 3 N 2 And the molar mass of metal (Ca) is 40 Thanks and regards, Kushagra

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12g of an alkaline earth metal gave 14.8g of its nitride.Atomic wt of that metal is

12g of an alkaline earth metal gave 14.8g of its nitride.Atomic wt of that metal is

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