# 12g of an alkaline earth metal gave 14.8g of its nitride.Atomic wt of that metal is

Ramesh V
70 Points
15 years ago

let the metal be M with atmic wt. be x

so 3M + N2 ---->M3N2

3x                   3x+28

so,  12/3x   = 14.8/(3x+28)

which in solving for x gives 40

the metal is calcium and its nitride is Ca3N2

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Ramesh
IIT Kgp - 05 batch

mohd atif chaudhary
17 Points
5 years ago
Mass of metal is 12g and Mass of metal nitride is 14.8gm so Mass of nitride ion is 2.8 gm.
By using equivalence law: Mass of metal / Mass of Nitride ion =Equivalent Mass of metal/14
12/2.8=3x/14
x=20 as x is equivalent weight by multiplying it with 2 which is valency of metal ion. We get 40.
Before x is 3 is used which is valency of Nitride and 14 is Mass of N .

mohd atif chaudhary
17 Points
5 years ago
Mass of metal is 12g and Mass of metal nitride is 14.8gm so Mass of nitride ion is 2.8 gm.By using equivalence law: Mass of metal / Mass of Nitride ion =Equivalent Mass of metal/14 12/2.8=3x/14x=20 as x is equivalent weight by multiplying it with 2 which is valency of metal ion. We get 40. Before x is 3 is used which is valency of Nitride and 14 is Mass of N .
4 years ago
Dear student,

Let the metal be M with atmic wt. be x
so 3M + N2 ---->M3N2
3x                3x+28

so,  12/3x   = 14.8/(3x+28)
Hence, x = 40
Hence, the metal is calcium and its nitride is Ca3N2
And the molar mass of metal (Ca) is 40

Thanks and regards,
Kushagra