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The KE of an electron emitted from tunsten surface is 3.06 eV. What voltae would be required to bring an electron to rest?

Vishrant Vasavada , 15 Years ago
Grade 11
anser 1 Answers
Ramesh V

Last Activity: 15 Years ago

KE of electron emitted frm tungsten surface is 3.06*1.602*10-19 J = 4.902*10-19

Let electron has been accelerated from rest through a potential difference of  V

  KE = qV = 1.6*10-19 *V = 4.902*10-19

         = 3.064 Volts

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