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Grade: 11
        The KE of an electron emitted from tunsten surface is 3.06 eV. What voltae would be required to bring an electron to rest?
10 years ago

Answers : (1)

Ramesh V
70 Points

KE of electron emitted frm tungsten surface is 3.06*1.602*10-19 J = 4.902*10-19

Let electron has been accelerated from rest through a potential difference of  V

  KE = qV = 1.6*10-19 *V = 4.902*10-19

         = 3.064 Volts


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Naga Ramesh
IIT Kgp - 2005 batch

10 years ago
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