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The KE of an electron emitted from tunsten surface is 3.06 eV. What voltae would be required to bring an electron to rest?

The KE of an electron emitted from tunsten surface is 3.06 eV. What voltae would be required to bring an electron to rest?

Grade:11

1 Answers

Ramesh V
70 Points
12 years ago

KE of electron emitted frm tungsten surface is 3.06*1.602*10-19 J = 4.902*10-19

Let electron has been accelerated from rest through a potential difference of  V

  KE = qV = 1.6*10-19 *V = 4.902*10-19

         = 3.064 Volts

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