Ramesh V
Last Activity: 15 Years ago
KE of electron emitted frm tungsten surface is 3.06*1.602*10-19 J = 4.902*10-19
Let electron has been accelerated from rest through a potential difference of V
KE = qV = 1.6*10-19 *V = 4.902*10-19
= 3.064 Volts
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