badge image

Enroll For Free Now & Improve Your Performance.

User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.

Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: Rs.

There are no items in this cart.
Continue Shopping
Grade: 11


A metal was irradiated by light of frequency 3.2 X 10^15 s^-1. The photoelectron produced has its KR, 2 times the KE of photoelectron which was produced when the same metal was irradiated with a light of frequency 2.0 X 10^15 s^-1. What is its work function?

11 years ago

Answers : (1)

Ramesh V
70 Points

K.E = hv -W

w is work fucnction in ev

h is planks constant = 4.14x10-15 ev-sec

K.E1 = hv1 -W  and K.E2 = hv2 -W

(hv1 -W) = 2.(hv2 -W )

W = h(2v2 -  v1)

     = 4.14x10-15 * (4 - 3.2)*x1015

     Work function = 3.312 eV


Please feel free to post as many doubts on our disucssion forum as you can. If you find any question difficult to understand - post it here and
we will get you the answer and detailed solution very quickly.We are all IITians and here to help you in your IIT JEE preparation. All the best.

Naga Ramesh
IIT Kgp - 2005 batch

11 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution

Course Features

  • 141 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!! Click Here for details